| Math Problem |
How to Approach the Problem |
| What are the perimeter and area of this square? |
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| For the perimeter, add up all of the sides: |
| 6 + 6 + 6 + 6 = 24 yards |
For the area, multiply the length times the width: |
| 6 x 6 = 36 square yards |
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| What are the perimeter and area of this rectangle? |
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| For the perimeter, add up all of the sides: |
| 18 + 8.5 + 18 + 8.5 = 53 miles |
For the area, multiply the length times the width: |
| 18 x 8.5 = 153 square miles |
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What is the length of the hypotenuse (the diagonal
side) of this right triangle? |
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The square of the hypotenuse equals the square
of one side plus the square of the other side: |
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| What are the perimeter and area of these triangles? |
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| For the perimeter of a triangle, add up all of its sides: |
- The perimeter of the first triangle is the length of
the base (b) plus the length of side 1 (s1) plus
the length of side 2 (s2).
- The perimeter of the second triangle is 3 + 4 + 5 = 12 cm.
- The perimeter of the third triangle is 6 + 5 + 5 = 16 cm.
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For the area of a triangle, multiply the base times the height, then
divide by 2: |
- The area of the first triangle is the base (b) times the
height (h) divided by 2.
- The area of the second triangle is (3 x 4) divided by 2 = 6 sq. cm.
- The area of the third triangle is (6 x 4) divided by 2 = 12 sq. cm.
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